Friday, 2 February 2018

Area of triangle


    1. Area of a triangle when we know the base and the height

      The area of a triangle is equal to half of base times height.
      A = 1a · h
      2
    2. Area of a triangle when we know the lengths of all three of its sides (Heron's formula)

      A = √s(s - a)(s - b)(s - c)
    3. Area of a triangle when we know two sides and the included angle

      The area of a triangle is equal to half of a product of two sides and sine of the angle between this sides.
      A = 1a · b · sin γ
      2
      A = 1a · c · sin β
      2
      A = 1b · c · sin α
      2
    4. Area of a triangle when we know three sides and circumradius

      A = a · b · с
      4R
    5. Area of a triangle when we know semiperimeter and in-radius

      The area of a triangle is equal to semiperimeter times in-radius.
      A = s · r

      where A - the area of a triangle,
      a, b, c - the length of sides BC,AC,AB accordingly,
      h - the height, the length of the altitude,
      α, β, γ - the angles,
      r - the length of the in-radius,
      R - the length of the circumradius,
      s = a + b + c  - the semiperimeter, or half of the triangle's perimeter.
      2
      REFERENCE FROM onlinemschool.com/math/formula/area/

    Friday, 19 January 2018

    Congruence of Triangles



    Congruence of Triangles
    If two geometrical figures are identical in shape and size then they are said to be congruent.
    The Method of Superposition.

    Step 1 : Take a trace copy of the Fig. 1. We can use Carbon sheet.

    Step 2 : Place the trace copy on Fig. 2 without bending, twisting and stretching.

    Step 3 : Clearly the figure covers each other completely.

    Therefore the two figures are congruent.



    Congruence of Triangles

    Two triangles are said to be congruent, if the three sides and the three angles of one triangle are respectively equal to the three sides and three angles of the other.
    Conditions for Triangles to be Congruent

    We know that, if two triangles are congruent, then six pairs of their corresponding parts (Three pairs of sides, three pairs of angles) are equal.

    But to ensure that two triangles are congruent in some cases, it is sufficient to

    verify that only three pairs of their corresponding parts are equal, which are given as axioms.

    There are four such basic axioms with different combinations of the three pairs of corresponding parts. These axioms help us to identify the congruent triangles.

    If ‘S’ denotes the sides, ‘A’ denotes the angles, ‘R’ denotes the right angle and ‘H’ denotes the hypotenuse of a triangle then the axioms are as follows:

    (i) SSS axiom          (ii) SAS axiom          (iii) ASA axiom        (iv) RHS axiom

    (i) SSS Axiom (Side-Side-Side axiom)

    If three sides of a triangle are respectively equal to the three sides of another triangle then the two triangles are congruent.
    (ii) SAS Axiom  (Side-Angle-Side Axiom)

    If any two sides and the included angle of a triangle are respectively equal to any two sides and the included angle of another triangle then the two triangles are congruent.
     (iii) ASA Axiom (Angle-Side-Angle Axiom)

    If two angles and a side of one triangle are respectively equal to two angles and the corresponding side of another triangle then the two triangles are congruent.
    (iv) RHS Axiom (Right angle - Hypotenuse - Side)

    If the hypotenuse and one side of the right angled triangle are respectively equal to the hypotenuse and a side of another right angled triangle, then the two triangles are congruent.


    Tuesday, 2 January 2018

    Multiplication-Napier bones method



    Multiplying a two-digit number with another two-digit number would require a Equation: {2} by Equation: {2} grid, for example Equation: {43}times{26}.
    Multiplying Equation: {264}times{53} would require a Equation: {3} by Equation: {2}grid.
    Follow the steps below to see how Napier’s method is used to calculate Equation: {43}times{26}.
    • The first step is to draw a Equation: {2} by Equation: {2} grid.
    • The second step is to draw a diagonal in each box. The diagonal line separates the tens and the units. Always write the tens above the diagonal line in each box.
    • Start by multiplying Equation: {4} and Equation: {2} to fill the left box on the top row.
    • Equation: {4}times{2}={8}
    • Write Equation: {0} and Equation: {8} to show that there are no tens.
    Multiplication diagram - Napiers' method: 4 x 2 = 08
    • Now multiply Equation: {3} and Equation: {2} to fill the right box on the top row.
    • Equation: {3}times{2}={6}
    Multiplication diagram - Napiers' method: 3 x 2 = 06
    • Next, multiply Equation: {4} and Equation: {6} to fill the left box on the bottom row.
    • Equation: {4}times{6}={24}
    • Remember to put the Equation: {2} above the diagonal.
    Multiplication diagram - Napiers' method: 4 x 6 = 24
    • Complete the grid by multiplying Equation: {3} and Equation: {6} to fill the right box on the bottom row.
    • Equation: {3}times{6}={18}
    Multiplication diagram - Napiers' method: 3 x 6 = 18
    After completing the grid, add the columns along the diagonals, starting at the bottom-right. We sometimes need to carry over from one diagonal to the next. To get the answer, read the totals down the left and to the right.
    Multiplication diagram - Napiers' method showing that 43 x 26 = 1,118
    Equation: {43}times{26}={1,118}
    REFERENCE FROM https://www.bbc.co.uk/education/guides/zvvg87h/revision/2
    Q